Copyright © 2000 David E. Rutherford
All Rights Reserved
We would like, now, to find the four-divergence of the current density of Eq. (105). This takes the form
After eliminating terms that cancel from the left and right-hand sides of Eq. (110), we are left with
where
is
the time component of the generalized electric field four-vector,
, from Eq.
(102). Simplifying Eq. (111) further, we get
, which
is equivalent to Eq. (76). Since
is the negative
four-divergence of the potential four-vector, it is a scalar quantity. We
can say then that
, where
is a scalar
quantity with the units of force per unit charge. The term,
, on the
right-hand side of Eq. (111) is the four-divergence of the extra current
density. It is, therefore, a scalar quantity with the units of charge per
unit four-dimensional volume or four-dimensional charge density. To simplify
this term, we say that
, where
is the
four-dimensional charge density. In order to simplify Eq. (111) still further,
we introduce the operator
,
which is the four-dimensional Laplacian operator. Putting all of this together, Eq. (111) becomes
where
is
a constant of proportionality. Since
represents
a matter density, we suspect that
represents
a scalar potential.
Now, remembering that the proper mass is
we can replace
in Eq.
(114) with the four-dimensional mass density,
, and
with the
four-dimensional charge density,
, to get
Multiplying both sides of Eq. (113) by
, we have
Inserting Eq. (115) into Eq. (116) and setting
, Eq. (116)
becomes
where
is
the gravitational potential.
Copyright © 2000 David E. Rutherford
All Rights Reserved
E-mail: drutherford@softcom.net